Group+3.1-4-EB

=**Representations of Motion**=
 * Group Members:** Rebecca Rabin, Jessica Tucker, Danielle Schimmenti
 * Period 4**
 * Date Completed:** September 17th, 2010
 * Date Due:** September, 20th, 2010


 * Objective/ Purpose:** What are the different types of motion? What is the best way to represent the motion?


 * Hypothesis:** The different types of motion: no motion, constant motion towards and away, increasing motion towards and away, and decreasing motion towards and away are best represented in a velocity vs. time graph.

a) Materials 1. Motion Detector and USB link 2. Spark timer 3. Timer tape
 * Procedure:**

b) Set-Up and Methods Time Graphs (Look to pictures below for example) 1. Connect USB Motion Detector to laptop 2. Open Data Studio and select //Create Experiment// 3. Select //setup// and open position vs. time graph, acceleration vs. time graph, and velocity vs. time graphs 4 . Set up Motion Detector in short range area with no possible motion detected. 5. Use a leveled surface (EX. Book, binder, folder, notebook) and distance yourself in front of and approximately 10 feet away from the Motion Detector 6. After positioning yourself, for increasing speed towards, start the ticker and begin walking towards the detector gradually increase your speed. After reaching the Motion detector stop the ticker and record your results. 7. For increasing speed away, position yourself directly in front of the Motion Detector, start the ticker, and move backwards gradually increasing your speed. After reaching approximately 10 feet away, stop the ticker and record your results. 8. For constant speed towards, position yourself approximately 10 feet away from the Motion Detector, start the ticker, and begin walking towards the detector at a constant speed. After reaching the Motion Detector, stop the ticker and record your results. 9. For constant speed away, position yourself directly in front of the Motion Detection, start the ticker, and move backwards at a constant speed. After reaching approximately 10 feet away, stop the ticker and record your results. 10. For decreasing speed towards, position yourself approximately 10 feet away from the Motion Detector, start the ticker and begin walking towards the detector gradually decreasing your speed. After reaching the motion detector, stop the ticker and record your results. 11. For decreasing speed away, position yourself directly in front of the Motion Detector, start the ticker, and move backwards gradually decreasing your speed. After reaching approximately 10 feet away, stop the ticker and record your results.

good to have pictures here. You can also use iMovie to show how you use the equipment...

Ticker Tape Diagrams (Look to pictures below for example) 1. Plug spark timer into an outlet. 2. Cut three pieces of timer tape approximately 12 inches long. 3. For increasing speed away, begin by sliding one piece of timer tape into the spark timer and turn the ticker on. Pull the timer tape through the spark timer while gradually increasing the speed. After the timer tape is completely through, turn the ticker off and record your results. 4. For constant speed away, begin by sliding a new piece of timer tape into the spark timer and turn the ticker on. Pull the timer tape though the spark timer while keeping a constant speed. After the timer tape is completely through, turn the ticker off and record your results. 5. For decreasing speed away, begin by sliding a new piece of time taper into the spark timer and turn the ticker on. Pull the timer tape through the spark timer while gradually decreasing the speed. After the timer tape is completely through, turn the ticker off and record your results.



**Data**:
looks great! Well, most of it! Maybe some of the vt and at graphs could be a little less bumpy??? 1. How can you tell that there is no motion on a… a. **Motion diagram** - A=0, V=0 b. **Ticker tape diagram** - Timer tapes results include only two dots c. **position vs. time graph** - Straight horizontal line at initial position d. **velocity vs. time graph** - Straight horizontal line at 0 e. **acceleration vs. time graph** - Straight horizontal line at 0
 * Analysis and Data Interpretation:**

2. How can you tell that your motion is steady on a… a. **Motion diagram** - A=0, equivalent arrow lengths b. **Ticker tape diagram** - Two dots remain at equivalent distances throughout the entire timer tape c. **position vs. time graph** - Constant Slope d. **velocity vs. time graph** - Straight horizontal line e. **acceleration vs. time graph** - Straight horizontal line

3. How can you tell that your motion is fast vs. slow on a… a. **Motion diagram**: if you are going faster, the velocity arrows will be getting bigger, if you are going slower, the velocity arrows will be getting smaller b. **Ticker tape diagram**: the farther apart the dots are, the faster the paper is being pulled c. **position vs. time graph**: the steeper the line is, the faster the object is moving d. **velocity vs. time graph**: the velocity is how fast or slow the object is moving so if the number is close to the origin, it moving slowly e. **acceleration vs. time graph**: if the line is far away from the origin, it will be moving faster than if the line is close to the origin This isn't true.

4. How can you tell that you changed direction on a… a. **Motion diagram**: the arrows will change directions b. **Ticker tape diagram**: the dots where you have changed direction will be darker or closer together because you have gone over them twice c. **position vs. time graph**: the slope of the graph will change signs (if it was positive before it will become negative) d. **velocity vs. time graph**: the line will reflect over the x-axis and then continue with the same slope e. **acceleration vs. time graph**: if you are accelerating when you change direction, the acceleration will stop while you are changing direction and then continue again This isn't true.

5. How can you tell that your motion is increasing on a… a. **Motion diagram**- If your acceleration is in the same direction as your velocity, then you are increasing motion. b. **Ticker tape diagram**- If the dots progressively spread out from the beginning of the diagram, then your motion is increasing. c. **position vs. time graph**- For when you are going in the positive direction (meaning the slope is positive) if the graph curves upward then your motion is increasing. However, if you are going in the negative direction (negative slope) and the line on the graph drops down then curves up then your motion is increasing. d. **velocity vs. time graph**- If the slope of the line is positive and on the positive half of the graph you are increasing in motion, and if the slope of the line is negative and is on the negative half of the graph you are increasing in motion. e. **acceleration vs. time graph**- If the line goes above the zero axis then you are increasing in motion. This isn't true.

6. How can you tell that your motion is decreasing on a… a. **Motion diagram**- If your acceleration is in the opposite direction of your velocity then you are decreasing in motion. b. **Ticker tape diagram-** If the dots progressively get closer together from the beginning of the diagram, then your motion is increasing.
 * c. position vs. time graph-** If the slope of the graph is negative and the line curves downward, then your motion is decreasing.
 * d. velocity vs. time graph-** If the slope of the line is positive on the negative half of the graph and if the slope of the line is negative on the positive half of the graph, then you are decreasing in motion.
 * e. acceleration vs. time graph-** If the line goes below the zero axis then you are decreasing in motion. This isn't true.

You need to go over the a-t graphs to make sure you understand them.

1. What are the advantages of representing motion using a… a. **Motion diagram** - Simple and useful diagrams that clearly depict the velocity, acceleration, and how they are related. b. **Ticker tape diagram** - Dots represent a very clear depiction of the speed (Increasing, decreasing, and constant) c. **position vs. time graph** - Allows for an easy understanding of where motion is in relevance to the Motion Detector. d. **velocity vs. time graph** - Easily depicts the relationship between speed and motion e. **acceleration vs. time graph** - Allows for an easy representation of acceleration, both increasing and decreasing, as well as velocity, both positive and negative.
 * Discussion Questions:**

2. What are the disadvantages of representing motion using a… a. **Motion diagram**: you cannot determine the exact velocity or acceleration of the object b. **Ticker tape diagram**: you cannot determine the direction, velocity, or speed of the object c. **position vs. time graph**: doesn’t really have a disadvantage unless something gets in the way of the sensor d. **velocity vs. time graph and acceleration vs. time graph**: there is error shown in this graph because we as humans do not walk steady, this affects the outcome because we cannot take an exact number

3. Define the following: a. **No motion**- 0 velocity, 0 acceleration b. **Constant speed**- no change in velocity, acceleration = 0 c. **Increasing speed**- positive velocity and positive acceleration, negative velocity and negative acceleration d. **Decreasing speed**- positive velocity and negative acceleration, negative velocity and positive acceleration

In this lab the purpose was satisfied for we graphed the different types of motion by utilizing the different types of motion diagrams and graphs, therefore we could then determine based on our data which diagram best represented motion. We first eliminated ticker tape and motion diagrams as good representation of motion, for the exact velocity or acceleration cannot be determined with these diagrams. When left between the position, velocity, and acceleration vs. time graphs, we concluded at the end of this experiment the the diagram/ graph the best represented motion was a velocity vs. time graph. This we concluded because the graph can tell you whether your velocity is positive or negative, whether your acceleration is positive or negative,and whether or not you changed direction. The fact that velocity vs. time graphs can vary so greatly based on what kind of motion is recorded using them, allows for very little left to be questioned or unknown. Unlike, a position vs. time graph, a velocity vs. time graph does not have one type of graph for decreasing motion. This is important for there is more than one instance in which something could be decreasing in motion. The v-t graph gives us the whole picture. This graph avoids the biggest case of ambiguity that arises with these diagrams and graphs, the issue of negative acceleration and velocity. Just because an object's velocity or acceleration is negative does not mean it is decreasing in motion. You must know an object's acceleration and velocity to determine whether it is increasing or decreasing in motion and a v-t graph tells u both whereas an acceleration graph for example does not. Certain issues may have arisen in this lab (as mentioned above in the analysis section) with the v-t graph, but these were subject to our medium of recording the data (via human motion). We still trust the velocity vs. time graph as the best representation of motion, and therefore our hypothesis was supported.
 * Conclusion:**
 * Results **

Error Several sources of error existed in this lab. First, the use of human motion and reflexes caused some error on our graphs and diagrams. In the graphs, the in-uniform motion of a person's steps along with our ability to accurately maintain constant, increasing, and decreasing speeds caused some fluctuation; and therefore affected our data. Also, in the ticker-tape diagrams how steady we were able to pull the tape through affected the accuracy of our results as well. Second, the motion sensor may not have picked up our motion correctly if we were standing too far away or if the book was not held at the correct level, which would have again caused the graphs to be less smooth and clean as they should be. Good sources of error.

Implications As stated previously, the errors that could have possibly existed could be easily addressed. In redoing this lab, we could take more precaution to our surroundings. By setting up our Motion Detector in a room with absolutely no other human motion and reflexes could have taken away any possible error caused by motions other than our own testings. As for accurately maintaining our desirable speeds, the only way to perfect this movement would be with computerized machinery. This concept is relevant in real-life applications pertaining to when we are measuring motion. Measuring motion is very important in specific situations where the position, velocity, acceleration is vital information needed. For example, measuring motion is crucial when launching a rocket. You can do either addressing error OR real life application, if you don't want to do both.

=A Crash Course in Velocity=
 * Group Members:** Rebecca Rabin, Jessica Tucker, Danielle Schimmenti
 * Period 4**
 * Date Completed:** September 24th, 2010
 * Date Due:** September, 27th, 2010

1. In pairs, generate a spark tape and use the data to create a position-time graph to find the average speed of a Constant Motion Vehicle (CMV). 2. Both algebraically and graphically, solve the following 2 problems. Then set up each situation and run trials to confirm your calculations. a. Find another group with a different CMV speed. Find the position where both CMV's will meet if they start //at least// 600 cm apart, move towards each other, and start simultaneously. b. Find the position where the faster CMV will catch with the slower CMV if they start //at least// 1 m apart, move in the same direction, and start simultaneously.
 * Objective:**

The slope of the faster CMV will be steeper than the slope of the slower CMV because the slope of a distance vs. time graph represents the velocity which will be greater for the faster CMV; also, the two CMV's will meet closer to the slower CMV's original position and the faster CMV will catch up to the slower CMV closer to the slower CMV's initial position because the slower CMV has a smaller velocity and will therefore be traveling less m/s from its original position than the faster CMV.
 * Hypothesis:**

a) Materials 1. Constant Motion Vehicle 2. Tape measure and/or meter sticks 3. Masking tape (about 30 cm/group) 4. Spark timer 5. Spark tape
 * Procedure:**

b) Set Up and Methods Collecting Data 1. Plug spark timer into an outlet. 2. Cut five pieces of timer tape approximately 1 meter long. 3. Pull one piece of timer tape through spark timer 4. Using tape, attach one end of the timer tape to the CMV with one battery. 5. Turn spark timer and CMV on allowing the CMV to pull the timer tape through and away from the spark timer. 6. Record data and repeat for each piece of tape. 7. Repeat steps 1-6 using the CMV with two batteries.

CMV Collision 1. Place the CMV with one battery facing directly 6 meters towards the CMV with two batteries. 2. Simultaneously start each CMV and record the results at which they collide. 3. Repeat steps 1-2 at least five times. media type="file" key="Movie 7.mov" width="300" height="300"media type="file" key="A Crash Course.mov" width="297" height="297" great to include these!

CMV Catch Up 1. Place CMV with one battery one meter in front of the CMV with two batteries. 2. Simultaneously start each CMV and record the location at which the fast CMV catches up with the slow CMV. 3. Repeat steps 1-2 at least five times. media type="file" key="Movie 9.mov" width="259" height="277"


 * Data:**
 * Slow CMV Ticker Tape ||
 * time (s) || position of dot (cm) ||
 * 0 || 0 ||
 * 0.1 || 1.49 ||
 * 0.2 || 2.82 ||
 * 0.3 || 4.17 ||
 * 0.4 || 5.49 ||
 * 0.5 || 6.8 ||
 * 0.6 || 7.92 ||
 * 0.7 || 9.2 ||
 * 0.8 || 10.41 ||
 * 0.9 || 11.68 ||
 * 1 || 13.08 ||
 * 1.1 || 14.46 ||
 * 1.2 || 15.7 ||
 * 1.3 || 17.02 ||
 * 1.4 || 18.49 ||
 * 1.5 || 19.75 ||
 * 1.6 || 21.32 ||
 * 1.7 || 22.67 ||
 * 1.8 || 23.88 ||
 * 1.9 || 25.31 ||
 * 2 || 26.49 ||
 * 2.1 || 27.82 ||
 * 2.2 || 29.41 ||
 * 2.3 || 30.48 ||
 * 2.3 || 30.48 ||

missing graph!
 * Fast CMV Ticker Tape ||
 * time (s) || position of dot (cm) ||
 * 0 || 0 ||
 * 0.1 || 3.27 ||
 * 0.2 || 6.82 ||
 * 0.3 || 10.49 ||
 * 0.4 || 14.15 ||
 * 0.5 || 17.98 ||
 * 0.6 || 21.83 ||
 * 0.7 || 25.61 ||
 * 0.8 || 29.49 ||
 * 0.9 || 33.49 ||
 * 0.9 || 33.49 ||

what is this? from other lab... need averages of these data
 * Slow and Fast CMV Collision ||  ||
 * Trial # || Position of collision* (m) ||
 * Trial 1 || 1.55 ||
 * Trial 2 || 1.42 ||
 * Trial 3 || 1.52 ||
 * Trial 4 || 1.59 ||
 * Trial 5 || 1.57 ||
 * Trial 5 || 1.57 ||
 * in relation to slow CMV's original position


 * Slow and Fast CMV Catch Up ||
 * Trial # || Meeting up position* (m) ||
 * Trial 1 || 1.7 ||
 * Trial 2 || 1.72 ||
 * Trial 3 || 1.68 ||
 * Trial 4 || 1.72 ||
 * Trial 5 || 1.69 ||
 * meeting up position is in relation to the fast CMV's original position
 * meeting up position is in relation to the fast CMV's original position

Calculations: __Objective 2__ (crash) v = d/t

Trial 1 v(slow CMV) = 13.251 cm/ s = .13251 m/s v(fast CMV) = 36.578 cm/s = .36578 m/s d(slow CMV) = 1.55 m d(fast CMV) = 6 - d(s) = 4.45 m t(s) =? t (f) = ?

.13251 m/s = d(s) / t .13251 m/s = 1.55 m / t t(s)= 11.7

.36578 m/s = d(f)) / t .36578 m/s = 4.45 m / t t(f)= 12.2 s

__Objective 3__ (catching up) v = d/t

Trial 1 v(slow CMV) = .13251 m/s v(fast CMV) = .36578 m/s d(fast CMV) = 1.70 m d(slow CMV) = d(f) - 1 = .70 m t = ?

.13251 m/s = .70 / t t = 5.3 s

__Objective 2__ Average Position: 1.53 m
 * Analysis**

Percent Error: Expected Values V(slow CMV) = -.13251 V(fast CMV) = .36578 d(slow CMV) = ? d(fast CMV) = 6m - d(s) t =?

.13251 m/s = d(s) / t .13251 t = d(s)

.36578 m/s = 6m - d(s) / t .36578 t = 6 - (.13251 t) .49829 t = 6 t =12.0 s

.36578 m/s = 6m - d(s) / 12.0 s d (s) = -1.61 m d(f) = 4.39 m

% error slow |1.53 - 1.61| / 1.61 X 100 = 4.97 % fast |4.47 - 4.39| / 4.39 X 100 = 1.82 %

nice!

__Objective 3__ Average Meet-up Point: 1.70 m

Percent Error: Expected Values

v(slow CMV) = .13251 m/s v(fast CMV) = .36578 m/s d(fast CMV) = ? d(slow CMV) = d(f) - 1 t = ?

.13251 m/s = d(f) -1 / t

.36578 m/s = d(f) / t .36578 t = d(f)

.13251 m/s = .36578 t - 1 / t .13251 t = .36578 t - 1 -.23327 t = -1 t = 4.28 s

.36578 (4.28) = d(f) d(f) = 1.57 m

d(s) = 1.57 m - 1 d(s) = .57 m

% error slow |1.70 - 1.57| / 1.57 X 100 = 8.28 % fast |.70 - .57| / .57 X 100 = 22.8 % good job on these calcs.


 * Discussion questions**

 It was okay to set the y-intercept equal to zero because it was impossible to get a negative distance based on the time in this lab. why? 3. **What is the meaning of the R2 value?**  The R2 value is the accuracy of your points based on the trend line that goes through them. The more accurate your points are, the closer to 1 your R2 value will be.  They would meet at exactly 3 meters. This is because that is halfway between where they started. If the car’s speeds were exactly the same, then they would be traveling the same distance in the same amount of time.
 * 1. Why is the slope of the position-time graph equivalent to average velocity?**
 * In order to get the slope of a line on a position-time graph, you have to take the change in y over the change in x. Since on a position-time graph distance is shown on the y-axis and time is shown on the x-axis, when you divide the distance by time to get velocity, you are also dividing the y-axis by the x-axis. Therefore, by getting the velocity you are also calculating the slop of a position-time graph. **
 * 2. Why was it okay to set the y-intercept equal to zero?**
 * 4. Where would the cars meet if their speeds were exactly equal**
 * 5. Sketch position-time graphs to represent the catching up and crashing situations. Show the point where they are at the same place at the same time.**
 * 6. Sketch velocity-time graphs to represent the catching up situation. Is there any way to find the points when they are at the same place at the same time?**

#5 and #6???


 * Conclusion**


 * Was the purpose satisfied? (was your hypothesis correct? Provide** __**specific**__ **evidence)** don't include these descriptions... conclusion should flow essay-like

Yes, the hypothesis we provided was proved to be correct. As seen in the Ticker Tape of Fast and Slow CMV graph, the fast CMV has a slope of 36.578 and the slow CMV has a slope of 12.251. This proves that the slope of the faster CMV is steeper than the slope of the slower CMV. Also, the two CMV’s meet up closer to the starting position of the slower CMV. When placed 6 meters apart, the two cars meet up at about 1.5m away from the starting point of the slow CMV. When the two cars were placed 1m apart and the fast CMV had to catch up to the slow CMV, it caught up closer to the slow CMV’s starting position. Each time, they caught up at around 1.7m. This is .7m away from the slow CMV and 1.7m away from the fast CMV. All of this information proves that our hypothesis was indeed correct. good to include actual values.


 * Errors (How much? Where did the error occur? Why did the error occur?)**

During the collision experiment, the slow car had 4.97% error and the fast car had 1.82% error. This error occurred when we were taking down the point at which the cars collided. It was impossible to tell exactly where the two cars collided so we tried our hardest to be as accurate as we could. Also, each time the experiment was performed we ended up with a different number. When doing the final calculation, we had to use the average of all of these trials therefore making the final number less accurate. The same types of problems with error occurred during the catching up experiment. Because the cars did not stop at the exact point where they caught up, we again had to be as accurate as possible without always being one hundred percent correct. It is impossible in this lab to get the exact point. Also, like in the first experiment, we got different numbers for each trial and had to average them together in order to calculate the final answer; this created error as well. good, well-explained

missing last part of conclusion

=Bombs Away=
 * Group Members:** Rebecca Rabin, Jessica Tucker, Danielle Schimmenti
 * Period 4**
 * Date Completed:** September 28th/29th, 2010
 * Date Due**: September, 30th, 2010


 * Objective/Purpose:** What is the acceleration of the falling body?


 * Hypothesis:** The acceleration of a falling body is 9.81 m/s^2. rationale?

a) Materials 1. Ticker Tape Timer  2. Timer Tape  3. Masking Tape  4. Mass  5. Clamp  6. Meter stick
 * Procedure:**

1. Using clamp, attach spark timer to top of cabinet door 2. Plug spark timer into outlet. 3. Cut timer tape approximately the length of cabinet door 4. Slide timer tape through top of spark timer and attach mass to tape 5. Turn spark timer on (be sure spark timer is set to 60 hertz) 6. Drop mass allowing the timer tape to fall through the spark timer 7. Measure distance from each using a meter stick 8. Record and graph your results
 * b) Set Up and Methods **

<span style="background-color: #ffff00; font-family: 'Comic Sans MS',cursive; font-size: 110%;">position is probably in (cm) not (m)
 * Calculations:**

t = (dot #)(1/60) t = (2)(1/60) t = .033s
 * Graph:**
 * Calculations**:

V =d/t V = .52/.017 V = 30.58 m/s

A = v/t A = 30.58/.033 A = 926.6 <span style="background-color: #ffff00; font-family: 'Comic Sans MS',cursive; font-size: 110%;">what are these?

**Percent Error:** __|Theoretical value – your value |__ x100 Theoretical value <span style="background-color: #ffff00; font-family: 'Comic Sans MS',cursive; font-size: 110%;">where did 658 come from? |__981 – 658__| x100 = **32.93%**

981

Percent Difference: |__your value - class average__| x100 class average __|874.426 - 658__| x100 = 981

It should be a line with a positive slope above the zero axis (in the positive region) starting from zero and extended away from the axis.
 * Discussion Questions:**
 * 1. Does the shape of your graph agree with the expected graph? Why or why not?** The shape of our graph does in fact agree with the expected graph. Falling objects increase their speed as they fall and therefore their accelerations increase which is what can be seen from our graph. Our R2 value is also .9997 which is extremely close to 1.
 * 2. How do your results compare to that of the class? (Use Percent difference to discuss quantitatively.)** <span style="background-color: #ffff00; font-family: 'Comic Sans MS',cursive; font-size: 110%;">**?**
 * 3. Did the object accelerate uniformly? How do you know?** Our free falling object did fall uniformly, increasing its velocity as it fell farther. We know this because the object began at rest and accelerated 658 m/s2, which means there was a clear change in velocity. Although our calculation were not extremely accurate, it was still the uniform acceleration. <span style="background-color: #ffff00; font-family: 'Comic Sans MS',cursive; font-size: 110%;">how do you know?
 * 4. What should the velocity-time graph of this object look like?**

Y = Ax^2 +Bx d= At^2 + Bt A = ½ a  B = vi  y= 329x^2 + 14.592 x  a = 2(329) a = 658 m/s^2 v-t equation <span style="background-color: #ffff00; font-family: 'Comic Sans MS',cursive; font-size: 110%;">y = 658x A greater force of gravity would cause acceleration due to gravity to be higher because gravity would pull the object to the floor at a faster rate. Greater air resistance would cause acceleration due to gravity to be lower because the resistance would make it harder for the object to accelerate at a fast rate. Also, lesser force of gravity would cause it to be lower because there would be less of a pull from gravity on the object if the force of gravity was weaker causing it to accelerate more slowly. Results <span style="background-color: #ffff00; font-family: 'Comic Sans MS',cursive; font-size: 110%;"> don't put these headings In this lab our purpose was satisfied for we did find the acceleration of a falling body, however, our hypothesis was not supported because the acceleration of our falling body was 658 m/s^2 whereas we hypothesized it would be 980 m/s^2. <span style="background-color: #ffff00; font-family: 'Comic Sans MS',cursive; font-size: 110%;">what about class results?
 * 5. Write down the expected equation of the line from this v-t graph (use specific information from your x-t graph.)**
 * 6. What factor(s) would cause acceleration due to gravity to be higher than it should be? Lower than it should be?**
 * Conclusion:**

Error The percent error in this lab was found to be 28.2%, which is a rather large percent. Two sources of error were friction created on the other end of the tape and how precise our measuring tools were. Friction was the biggest source of error in our lab because as the tape fed through the spark timer we were creating friction on the other end by holding on to the tape and letting it slide through our fingers so it would no twist. This caused our results to be relatively far from the expected value for acceleration and an outlier of the class values. A second although much less significant source of error was the issue of how precise our tools for measurement and therefore our measurements were because we had to estimate the second decimal place of each measurement.

Implications In order to avoid error in this lab in the future we would not create friction on the other end of the tape because it affected the acceleration of the falling body. <span style="background-color: #ffff00; font-family: 'Comic Sans MS',cursive; font-size: 110%;">how?